33x^2+44x+12=0

Solution for 33x^2+44x+12=0 equation:

33x^2+44x+12=0

a = 33; b = 44; c = +12;
Δ = b2-4ac
Δ = 442-4·33·12
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{22}}{2*33}=\frac{-44-4\sqrt{22}}{66}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{22}}{2*33}=\frac{-44+4\sqrt{22}}{66}
$